**Answer to Prob 19,
L4, p21**

slope = -12480 K

**Answer to Prob 20,
L4, p21**

1.73 x 10^{-19}J

**Answer to Prob 21,
L4,p23**

5.6 x 10^{-21}
J

**Answer to Prob 22,
L4,p24**

a)

0.79 x 106 at 40°C

5.2 x 106 at 55°

b) 205 m/s

**Answer to Prob 23,
L4,p25**

from the graph, c = 31.60 = ln A

**Answer to Prob 24,
L5,p28**

a)

247.7 m/s at 40°C

259.3 m/s at 70°C

b)

247.7 x 10^{-16} m^{3}

2.593 x 10^{-16}
m^{3}

c)

1.49 x 10^{8}

1.562 x 10^{8}

**Answer to Prob 25,
L5,p28 **

a) at 40°C, *N*
= 2.345 x 10^{25} m^{-3} at 70°C, *N* = 2.14 x 10^{25}
m^{-3}

b) *Z*_{AA}
=6.81 x 10^{34} m^{-3}.s^{-1} *Z*_{AA}
= 5.94 x 10^{34} m^{-3}.s^{-1}

c) *Z*_{AA}
at 70°C is less than *Z*_{AA} at 40°C

**Answer to Prob 26,
L5, p31**

*c* = 302.6 m/s*
k* = 2.07 x 10

**Answer to Prob 27,
L5, p32**

*E*a is an empirical
value (measured from experiment), i.e. not calculated from scratch.

Doesn’t apply to reactions
in solution

quantum effects are ignored

internal motions of atoms in the molecules are ignored.

**Answer to Prob 30,
L6, p37**

5.69 x 10^{12}
s^{-1}

6.21 x 10^{12} s^{-1}

9.86 x 10^{12} s^{-1}

**Answer to Prob 32,
L6, p38**

Only D *G°
*^{‡}, D *H°
*^{‡}, D *S°
*^{‡}, and temperature.

**Answer to Prob 33,
L6, p39**

Ea » 83 kJ/mol ;
D *H°
*^{‡} » 80.6 kJ/mol

**Answer to Prob 34,
L6, p39**

61.9 kJ/mol , 61.5 kJ/mol
i.e. D *H°
*^{‡} = 62 +/- 2 kJ/mol

**Answer to Prob 7, L2,p10**

a) 2nd ord eq.: calculate
the reciprocal of reactant conc’n at various times, and plot against time.
slope equals _{2}*k*, the rate constant.

2nd ord unequal calculate
the y values according to the eq’n 5, p10, and plot against time. Slope =
(a-b) x _{2}*k*

**Answer to Prob 7, L2,p10**

don’t know what this is!!

wrongs | prec’n % |
---|---|

0.000077 | 0.37 |

0.000048 | 0.23 |

0.000036 | 0.17 |

0.000098 | 0.47 |

0.00011 | 0.53 |

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